Given a string, find the length of the longest substring without repeating characters.
Examples:
Given "abcabcbb"
, the answer is "abc"
, which the length is 3.
Given "bbbbb"
, the answer is "b"
, with the length of 1.
Given "pwwkew"
, the answer is "wke"
, with the length of 3. Note that the answer must be a substring, "pwke"
is a subsequence and not a substring.
思路一:
使用hash表
- 变量start记录了子串的起点。
- used用来记录字符串的字符,key是字符c,value是索引i。
- 如果字符之前出现过,start右移,否则,更新最大长度。
实现:1
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10def lengthOfLongestSubstring(self, s):
used = {}
max_len = start = 0
for i, c in enumerate(s):
if c in used and start <= used[c]:
start = used[c] + 1
else:
max_len = max(max_len, i-start+1)
used[c] = i
return max_len
备注:注意当前子串的长度为i-start+1。